If the A.M. between $a$ and $b$ is $m$ times their H.M. thena : $b=$

$\sqrt{m}-\sqrt{m-1}: \sqrt{m+1}+\sqrt{m-1}$

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

If the A.M. between

a

and

b

m

times their H.M. thena :

b=

View answer and explanation

Correct option: A

\sqrt{m}+\sqrt{m-1}: \sqrt{m}-\sqrt{m-1}

Option A (

\sqrt{m}+\sqrt{m-1}: \sqrt{m}-\sqrt{m-1}

) is correct because using the relationship between AM and HM, and applying componendo and dividendo, we arrive at the given ratio.

Practice All Chapter MCQs →

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a,x,b

b,y,c

{x^2},{b^2},{y^2}

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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A P

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G P

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\frac{3}{4}