When a radioactive isotope $_{88}{{\rm{R}}^{228}}$ decay in series by the emission of $3\,\alpha $-particles and ${\rm{\beta }}$-particle, the isotope finally formed is

JEE PHYSICS MCQ: NUCLEI

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When a radioactive isotope

_{88}{\mathrm{R}^{228}}

decay in series by the emission of

3\,\alpha

-particles and

\mathrm{\beta }

-particle, the isotope finally formed is

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Correct option: C

_{83}{\mathrm{X}^{216}}

Option C (₈₃X²¹⁶) is correct because it correctly accounts for the decrease in mass number and atomic number due to the emission of 3 alpha particles and 1 beta particle.

JEE PHYSICS MCQ: NUCLEI

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