If the line $y-\sqrt{3} x+3=0$ cuts the parabola $y^2=x+2$ at $A$ and $B$, then $P A \cdot P B$ is equal to [where, $P=(\sqrt{3}, 0)$ ]

JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1

If the line

y-\sqrt{3} x+3=0

cuts the parabola

y^2=x+2

A

and

B

, then

P A \cdot P B

is equal to [where,

P=(\sqrt{3}, 0)

]

View answer and explanation

Correct option: A

\frac{4(\sqrt{3}+2)}{3}

Option A (

\frac{{4(\sqrt{{3}}+2)}}{{3}}

) is correct because it represents the value of PA * PB calculated using parametric equations.

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