JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

Let

a

b

and

c

be in GP with common ratio

r

, where

a \ne 0

and

0 < r \le \frac{1}{2}

. If 3a, 7b and 15c are the first three terms of an AP, then the 4th term of this AP is

View answer and explanation

Correct option: C

Option C (a) is correct because after using the properties of GP and AP, and solving for the common ratio, the 4th term of the AP is found to be a.

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a,x,b

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{x^2},{b^2},{y^2}

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y

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y=x-2

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\log \left(\frac{a}{3 b}\right)

A P

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G P

a, b, c

\frac{3}{4}