JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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A solid ball of radius

R

has a charge density

\rho

given by

\rho=\rho_0\left(1-\frac{r}{R}\right)

for

0 \leq r \leq R

. The electric field cutside the ball is

View answer and explanation

Correct option: A

\frac{\rho_0 R^3}{12 \varepsilon_0 r^2}

The correct answer is A. The electric field outside the ball is calculated using Gauss's law, integrating the charge density over the volume of the sphere.

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