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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡x→1(2−1x)tan⁡(π/2x)=\lim\limits_{x \to 1} {\left( {2 - \frac{1}{x}} \right)^{\tan \left( {\pi /2x} \right)}} =
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Correct option: B
e2/π{e^{2/\pi }}
Option B (e2/π{e^{2/\pi }}) is correct because the limit can be evaluated by substituting and using standard limit formulas.

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