JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

The value of

I=\int\limits_{0}^{\pi / 2} \frac{(\sin x+\cos x)^2}{\sqrt{1+\sin 2 x}} d x

, is

View answer and explanation

Correct option: C

2

The correct answer is C (

2

) because the integral simplifies to

\int_0^{\pi/2} (\sin x + \cos x) dx

, which evaluates to 2.

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