The de-Broglie wavelength associated with a particle of mass $\mathrm{m}$ and energy $\mathrm{E}$ is $\mathrm{h} / \sqrt{\mathrm{2 m E}}$. The dimensional formula for Planck's constant is :

$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$

$\left[\mathrm{MLT}^{-2}\right]$

$\left[\mathrm{M}^2 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

1 Easy

1 of 1

Application +4 | -1

The de-Broglie wavelength associated with a particle of mass

\mathrm{m}

and energy

\mathrm{E}

\mathrm{h} / \sqrt{\mathrm{2 m E}}

. The dimensional formula for Planck's constant is :

View answer and explanation

Correct option: B

\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]

Option B (

\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]

) is correct because the de-Broglie wavelength is given, and we can solve for Planck's constant (h) dimensionally.