$\begin{gathered} {\text{Borax}}\xrightarrow[{{\text{ Excess }}}]{\Delta }{\text{NaB}}{{\text{O}}_2} + {\text{(B)}} \hfill \\ {\text{(B)}} + {\text{Nickel oxide}}\xrightarrow{\Delta }{\text{(C)}} \hfill \\ \end{gathered}$ Compound $\mathrm{C}$ and its colour is

$\mathrm{Ni}\left(\mathrm{BO}_2\right)_3$, brown

JEE CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

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Understanding +4 | -1

\begin{gathered} {\text{Borax}}\xrightarrow[{{\text{ Excess }}}]{\Delta }{\text{NaB}}{{\text{O}}_2} + {\text{(B)}} \quad \\ {\text{(B)}} + {\text{Nickel oxide}}\xrightarrow{\Delta }{\text{(C)}} \quad \\ \end{gathered}

Compound

\mathrm{C}

and its colour is

View answer and explanation

Correct option: C

\mathrm{Ni}\left(\mathrm{BO}_2\right)_2

, yellow

Option C (

\mathrm{Ni(BO_2)_2}

, yellow) is correct because Nickel oxide reacts with Boric anhydride to form Nickel metaborate, which is yellow in color.

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