In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of $2\,\,m$ when the cell is shunted by a $5\,\,{\rm{\Omega }}$ resistance; and is at a length of $3\,\,m$ when the cell is shunted by a $10\,\,{\rm{\Omega }}$ resistance. The internal resistance of the cell is, then

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of

2\,\,m

when the cell is shunted by a

5\,\,\mathrm{\Omega }

resistance; and is at a length of

3\,\,m

when the cell is shunted by a

10\,\,\mathrm{\Omega }

resistance. The internal resistance of the cell is, then

View answer and explanation

Correct option: B

10\,\,\mathrm{\Omega }

Option B (

10 \Omega

) is correct because the internal resistance is calculated using the potentiometer principle and the given shunt resistances and balancing lengths.