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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Application +4 | -1
The products A and B are
(CH3)3C−CHO→ (ii) H+(i) con.NaOHA+B\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{CHO} \xrightarrow[\text { (ii) } \mathrm{H}^{+}]{\text {(i) } \mathrm{con.}{\mathrm{NaOH}}} \mathrm{A}+\mathrm{B}
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Correct option: C
A=(CH3)3C−CH2−OH,B=(CH3)3C−COOH\mathrm{A}=\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{CH}_2-\mathrm{OH}, \mathrm{B}=\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{COOH}
Option C (A=(CH3)3C-CH2-OH, B=(CH3)3C-COOH) is correct because the reaction is a Cannizzaro reaction, which produces an alcohol and a carboxylic acid.

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