JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Medium

1 of 1

Understanding +4 | -1

Statement I: The value of velocity of light is

3 \times 10^8 \mathrm{~ms}^{-1}

and acceleration due to gravity is

10 \mathrm{~ms}^{-2}

and the mass of proton is

1.67 \times 10^{-27} \mathrm{~kg}

.
Statement II: The value of time in such a system is

3 \times 10^7 \mathrm{~s}

View answer and explanation

Correct option: B

Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I

Option D is correct because both statements are true, but Statement II does not explain Statement I. Statement II is derived from Statement I using dimensional analysis.

More Questions from UNITS & MEASUREMENTS

Practice All Chapter MCQs →

Assertion :

\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

has the unit

\mathrm{ms}^{-1} \text {. }

Reason: Acceleration has the dimensions of

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
Statement-II: Numerical value of constant of proportionality can be found from experiments only The dimensions of torque are The physical quantity having the dimensions

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

is A quantity X is given by

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

, where

{\varepsilon _0}

is the permittivity of free space, L is a length,

{\Delta V}

is a potential difference and

{\Delta t}

is a time interval. The dimensional formula for X is the same as that of