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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
lim⁡x→0sin⁡2x2−1+cos⁡x\lim _{x \rightarrow 0} \frac{\sin ^2 x}{\sqrt{2}-\sqrt{1+\cos x}} equals
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Correct option: A
424 \sqrt{2}
Option A (424 \sqrt{2}) is correct because after applying L'Hopital's rule and trigonometric identities, the limit evaluates to 424 \sqrt{2}.

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