JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

f(x)= \begin{cases}\frac{\sin [x]}{[x]}, & {[x] \neq 0,} \\ 0, & \text [x] \neq 0,\end{cases}

where

[x]

denotes the greatest integer less than or equal to

x

. Then,

\lim \limits_{{x \rightarrow 0}} f(x)

equals

View answer and explanation

Correct option: D

None of these

The correct answer is D (None of these) because the limit does not exist as the left-hand limit and right-hand limit are not equal.

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