JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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A bee of mass

0.000087 \mathrm{~kg}

sits on a flower of mass

0.0123 \mathrm{~kg}

. What is the total mass supported by the stem of the flower up to appropriate significant figures?

View answer and explanation

Correct option: D

0.012 \mathrm{~kg}

Option D (

0.012 \mathrm{~kg}

) is correct because the sum of the masses must be rounded to the least number of significant figures, which is three in this case, based on the flower's mass.

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\mathrm{ms}^{-1} \text {. }

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\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
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\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

is A quantity X is given by

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

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{\varepsilon _0}

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{\Delta V}

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{\Delta t}

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