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JEE PHYSICS MCQ: WAVES

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Analyzing +4 | -1
The displacement of a string is given by y(x,t)=0.06sin⁡(2πx/3)cos⁡(120πt)y(x, t)=0.06 \sin (2 \pi x / 3) \cos (120 \pi t), where xx and yy are in metre and tt in second. The length of the string is 1.5 m1.5 {~m} and its mass is 3.0×10−2 kg3.0 \times 10^{-2} {~kg}.
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Correct option: C
It is the result of superposition of two waves of wavelength 3 m3 {~m}, frequency 60 Hz60 {~Hz} each travelling with a speed of 180 m/s180 {~m} / {s} in opposite direction.
Option C (It is the result of superposition of two waves of wavelength 3 m3 {~m}, frequency 60 Hz60 {~Hz} each travelling with a speed of 180 m/s180 {~m} / {s} in opposite direction) is correct because the given equation represents a stationary wave formed by the superposition of two waves with the specified wavelength, frequency, and speed.

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