JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

The thrust developed by a rocket-motor is given by

F = mv + A\left( {{p_1} - {p_2}} \right)

, where m is the mass of the gas ejected per unit time,

v

is velocity of the gas, A is area of cross-section of the nozzle,

{p_1}.{p_2}

are the pressures of the exhaust gas and surrounding atmosphere. The formula is dimensionally

View answer and explanation

Correct option: A

Correct

Option A (Correct) is correct because each term in the equation has the dimensions of force (MLT^-2), making the equation dimensionally consistent.

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