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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
Sum of digits in the unit’s place formed by the digits 1, 2, 3 and 4 taken all at a time is
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Correct option: B
60
Option B (60) is correct because each digit appears in the unit's place 3!3! times, and the sum of the digits is 1+2+3+4=101+2+3+4=10, so the sum of digits in the unit's place is 3!×10=603! \times 10 = 60.

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