Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
1 of 1
Application +4 | -1
If ∫[x][x]+1  f(t)  dt=[x]\int \nolimits_{\left[ x \right]}^{\left[ x \right] + 1} \,\,f\left( t \right)\,\,dt = \left[ x \right],〗 then the value of ∫−24  f(x)  dx\int \nolimits_{ - 2}^4 \,\,f\left( x \right)\,\,dx is equal to
View answer and explanation
Correct option: D
3\mathrm{3}
Option D (3) is correct because the integral from [x] to [x]+1 of f(t) dt equals [x], allowing us to sum the integrals from -2 to 4 to get 3.
Solution approach
  1. Correct Answer + Core Reason: 3. The integral is evaluated by summing the integrals over integer intervals.

    Step-by-Step Solution:

    Step 1: Given ∫[x][x]+1  f(t)  dt=[x]\int \nolimits_{\left[ x \right]}^{\left[ x \right] + 1} \,\,f\left( t \right)\,\,dt = \left[ x \right]

    Step 2: Evaluate the integral from -2 to 4 by breaking it into intervals of length 1 based on the greatest integer function.

    Step 3: ∫−2−1f(x)  dx=−2\int \nolimits_{ - 2}^{ - 1} f\left( x \right)\,\,dx = -2, ∫−10  f(x)  dx=−1\int \nolimits_{ - 1}^0 \,\,f\left( x \right)\,\,dx = -1, ∫01  f(x)  dx=0\int \nolimits_0^1 \,\,f\left( x \right)\,\,dx = 0, ∫12  f(x)  dx=1\int \nolimits_1^2 \,\,f\left( x \right)\,\,dx = 1, ∫23  f(x)  dx=2\int \nolimits_2^3 \,\,f\left( x \right)\,\,dx = 2, ∫34  f(x)  dx=3\int \nolimits_3^4 \,\,f\left( x \right)\,\,dx = 3

    Step 4: Sum the integrals: ∫−24  f(x)  dx=−2−1+0+1+2+3=3\int \nolimits_{ - 2}^4 \,\,f\left( x \right)\,\,dx = -2 - 1 + 0 + 1 + 2 + 3 = 3

    Why other options are wrong:
    - Option A: 1 is incorrect because it only considers a portion of the integral range or makes a calculation error.
    - Option B: 2 is incorrect because it only considers a portion of the integral range or makes a calculation error.
    - Option C: -2 is incorrect because it only considers a portion of the integral range or makes a calculation error.

    Key Concepts:
    - Definite Integrals
    - Greatest Integer Function
    - Properties of Integrals

    Memory Aids:
    - Remember to break the integral into intervals based on the greatest integer function.

    Quick Tips:
    - Always consider the properties of the greatest integer function when dealing with integrals involving it.

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Question image

Use + and − to zoom, arrow keys or drag to pan, Escape to close.