JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The general value of

\theta

satisfying the equation

2\,\,{\sin ^2}\,\,\theta - 3\,\,\sin \,\,\theta - 2 = 0

View answer and explanation

Correct option: A

n\pi + {\left( { - 1} \right)^{n + 1}}\,\,\frac{\pi }{6}

Option A (

n\pi + {\left( { - 1} \right)^{n + 1}}\,\frac{\pi }{6}

) is correct because it represents the general solution to the trigonometric equation

2{\sin ^2}\,\theta - 3\,\sin \,\theta - 2 = 0

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