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JEE CHEMISTRY MCQ: HYDROCARBONS

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Application +4 | -1

C{H_3} - HC= C{H_2} + HCl\xrightarrow[{{\text{Peroxide}}}]{{{\text{Benzoyl}}}}?

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Correct option: A

2 – chloropropane

Option A (2 – chloropropane) is correct because the reaction follows Markovnikov's rule in the presence of peroxide.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

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