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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The sum to nn terms of the infinite series 1.32+2.52+3.72+...∞{1.3^2} + {2.5^2} + {3.7^2} + ...\infty
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Correct option: A
n6(n+1)(6n2+14n+7)\frac{n}{6}\left( {n + 1} \right)\left( {6{n^2} + 14n + 7} \right)
Option A is correct because the sum to n terms of the given series is derived by expressing the general term, summing it, and simplifying the expression.

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