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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The coefficient of xn{x^n} in the expansion of (1+x22!+x44!+…)2,{\left( {1 + \frac{{{x^2}}}{{2!}} + \frac{{{x^4}}}{{4!}} + \ldots } \right)^2},, when nn is odd, is
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Correct option: C
0
Option C (0) is correct because the expression simplifies to cosh2(x), which only contains even powers of x. Therefore, the coefficient of x^n when n is odd is 0.

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