JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

\lim \limits_{{n \rightarrow \infty}} n \cos \left(\frac{\pi}{4 n}\right) \sin \left(\frac{\pi}{4 n}\right)=k

, then

k

View answer and explanation

Correct option: A

\frac{\pi}{4}

Option A (

\frac{{\pi}}{{4}}

) is correct because applying the limit and using the small angle approximation yields

\frac{{\pi}}{{4}}

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