JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

A radioactive element

_{90}{X^{238}}

decays into

_{83}{Y^{222}}

. The number of

\beta -

particles emitted are

View answer and explanation

Correct option: D

Option D (1) is correct because after accounting for alpha decay, one beta particle emission is needed to match the final atomic number.

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