NEET UG CHEMISTRY MCQ: HYDROCARBONS

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Which of the following would not give 2phenylbutane as the major product in a FriedelCrafts alkylation reaction?

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Correct option: C

Butanoyl chloride

+\mathrm{AlCl}_3

then

\mathrm{Zn}, \mathrm{HCl}

Option C (Butanoyl chloride +

\mathrm{AlCl}_3

then

\mathrm{Zn}, \mathrm{HCl}

) is correct because it undergoes Friedel-Crafts acylation followed by reduction, resulting in a straight chain alkyl group instead of 2-phenylbutane.

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