JEE PHYSICS MCQ: MOTION IN PLANE

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Analyzing +4 | -1

For a projectile if

\alpha

is the angle of projection,

R

is the range,

h

is the maximum height,

T

is the time of flight then

View answer and explanation

Correct option: C

\tan \alpha=\frac{4 \mathrm{~h}}{\mathrm{R}}, \mathrm{h}=\frac{\mathrm{gT}^2}{8}

Option C (

\tan \alpha=\frac{4 \mathrm{~h}}{\mathrm{R}}, \mathrm{h}=\frac{\mathrm{gT}^2}{8}

) is correct because it correctly relates the angle of projection, range, maximum height, and time of flight for a projectile.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}