JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Understanding +4 | -1

In finding the electric field using Gauss law the formula

\left| E \right| = \frac{{{q_{\mathrm{enc}}}}}{{{\varepsilon _0}\left| A \right|}}

is applicable. In the formula,

{\varepsilon _0}

is permittivity of free space,

A

is the area of Gaussian surface and

{q_{\mathrm{enc}}}

is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?

View answer and explanation

Correct option: A

Only when the Gaussian surface is an equipotential surface and

|E|

is constant on the surface.

Option A (Only when the Gaussian surface is an equipotential surface and

|E|

is constant on the surface) is correct because Gauss's law is easily applied when the electric field is constant and perpendicular to the Gaussian surface.

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