JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

\lim _{n \rightarrow \infty}\left(\sqrt{n^2-n-1}+n \alpha+\beta\right)=0

, then

8(\alpha+\beta)

is equal to

View answer and explanation

Correct option: C

-4

Option C (-4) is correct because, after rationalizing and comparing coefficients,

8(\alpha + \beta)

equals -4.

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