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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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An electric dipole consists of two opposite charges each 0.05μC\mathrm{\mu C} separated by 30 mm. The dipole is placed in an uniform external electric field of 106NC−1.{10^6}\mathrm{N}{\mathrm{C}^{ - 1}}. The maximum torque exerted by the field on the dipole is
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Correct option: D
1.5×10−3N−m1.5 \times {10^{ - 3}}\mathrm{N} - \mathrm{m}
Option D (1.5×10−3N−m1.5 \times {10^{ - 3}}\mathrm{N} - \mathrm{m}) is correct because it is calculated using the formula for maximum torque on a dipole in an electric field, τ=pE\tau = pE, where pp is the dipole moment and EE is the electric field.

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