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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
Area of quadrilateral formed by joining the focii of the ellipse, x216+y212=1\frac{x^2}{16}+\frac{y^2}{12}=1 and x212+y216=1\frac{x^2}{12}+\frac{y^2}{16}=1 is (in sq. units)
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Correct option: D
8
Option D (2xyℓn(xy)=x2+C2 x y \ell n(x y)=x^2+C) is correct because by rearranging the differential equation and integrating, we arrive at the given solution.

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