JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Let

\mathrm{x}, \mathrm{y}, \mathrm{z}

be positive real numbers such that

x+y+z=12

and

x^{3} y^{4} z^{5}=(0.1)(600)^{3}

. Then

x^{3}+y^{3}+z^{3}

is equal to:

View answer and explanation

Correct option: B

216

Option B (216) is correct because by using AM-GM inequality and the given condition, we find that x=3, y=4, z=5, and thus

x^3 + y^3 + z^3 = 216

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