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JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1
The equations of the tangents to the circle x2+y2−6x+4y−12=0{x^2} + {y^2} - 6x + 4y - 12 = 0 which are parallel to the line 4x+3y+5=04x + 3y + 5 = 0, are
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Correct option: C
4x+3y+19=04x + 3y + 19 = 0 and 4x+3y−31=04x + 3y - 31 = 0
Option C (4x + 3y + 19 = 0 and 4x + 3y - 31 = 0) is correct because these are the tangent lines found by using the perpendicular distance from the center of the circle to the tangent equals the radius.

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