JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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The value of definite integral

\int\limits_{ - \pi }^\pi {\frac{{2x\left( {1 + \sin x} \right)}}{{1 + {{\cos }^2}x}}} \,dx

is:

View answer and explanation

Correct option: C

{\pi ^2}

Option D (

{\pi ^2}

) is correct because it is the value of the definite integral after applying properties of definite integrals and trigonometric substitutions.

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