JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

I=\int_{\pi / 4}^{\pi / 3}\left(\frac{8 \sin x-\sin 2 x}{x}\right) d x

. Then

View answer and explanation

Correct option: C

I > \sqrt 3 - \frac{\pi }{6}

The correct answer is C (

I > \sqrt 3 - \frac{\pi }{6}

) because the integral I is bounded below by the given expression, which is derived by using the minimum value of

\frac{{\sin x}}{x}

in the interval.

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