JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

S_1=\Sigma n, S_2=\Sigma n^2, S_3=\Sigma n^3

, then the value of

\lim \limits_{{n \rightarrow \infty}} \frac{S_1\left(1+\frac{S_3}{8}\right)}{{S_2}^2}

is equal to

View answer and explanation

Correct option: D

\frac{9}{64}

Option D (

\frac{9}{64}

) is correct because after substituting the summation formulas and simplifying, the limit evaluates to

\frac{9}{64}

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