Skip to main content
Back to LIMITS

JEE MATHEMATICS MCQ: LIMITS

1 Easy
1 of 1
Analyzing +4 | -1
If Sn=(1−tan⁡4π23)(1−tan⁡4π24)…(1−tan⁡4π2n).S_n=\left(1-\tan ^4 \frac{\pi}{2^3}\right)\left(1-\tan ^4 \frac{\pi}{2^4}\right) \ldots\left(1-\tan ^4 \frac{\pi}{2^n}\right) .

The value of lim⁡n→∞Sn\lim \limits_{{n \rightarrow \infty}} S_n, is
View answer and explanation
Correct option: C
π332\frac{\pi^3}{32}
Option C (π332\frac{\pi^3}{32}) is correct because the limit of the given product is evaluated using trigonometric identities and limit properties.

More Questions from LIMITS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.