JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim\limits_{n \to \infty } \left( {\frac{{{1^2}}}{{1 - {n^3}}} + \frac{{{2^2}}}{{1 - {n^3}}} + ... + \frac{{{n^2}}}{{1 - {n^3}}}} \right)

is equal to

View answer and explanation

Correct option: D

- \frac{1}{6}

Option D (-1/6) is correct because after summing the series and taking the limit, the expression evaluates to -1/6.

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