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JEE CHEMISTRY MCQ: CHEMICAL KINETICS

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Rate of a chemical reaction becomes 4 times when concentration of reactant is made 4 times. If 50%50 \% of reaction occurs in 1414sec1414 \mathrm{sec}, how long would it take for completion of 75%75 \% reaction?
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Correct option: B
2828 second
The correct answer is B (2828 second) because the reaction is first order, and 75% completion takes twice the time for 50% completion.

More Questions from CHEMICAL KINETICS

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The reaction A2+B2β†’2AB\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB} follows the mechanism

A2β‡Œkβˆ’1k1A+AΒ (fast)Β A+B2β†’k2AB+BΒ (slow)Β A+Bβ†’ABΒ (fast)Β \begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

The overall order of the reaction is:
For the first order reaction with the rate constant kk, which expression gives the rate half-life period? (Initialconc.=a)(Initial\mathrm{ }conc.\mathrm{ } = a) Which of the following is a zero order reaction? For a certain reaction involving a single reactant, it is found that C0TC_0 \sqrt{T} is constant, where C0C_0 is the initial concentration of the reactant and TT is the half-life. What is the order of the reaction? Arrhenius equation is The energy of activation for an uncatalysed reaction is 100 kJ/mol.100 \mathrm{~kJ/mol}. Presence of a catalyst lowers the energy of activation by 75%75 \%. The log⁑10K2K1\log _{10} \frac{K_2}{K_1} of the ratio of rate constant of catalysed and uncatalysed reactions at 27∘C27^{\circ} \mathrm{C} is?

Assume the frequency factor is same for both reactions. (Given 2.303Γ—8.314=19.1472.303 \times 8.314=19.147)
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