When two resistances ${R_1}\,\,{\rm{and}}\,\,{R_2}$ are connected in series, they consume ${\rm{12}}\,\,{\rm{W}}$ powers. When they are connected in parallel, they consume ${\rm{50}}\,\,{\rm{W}}$ powers. What the ratio of the powers of ${R_1}\,\,{\rm{and}}\,\,{R_2}$ ?

$\begin{array}{*{20}{l}} {{\rm{3/2}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{1/4}}} \end{array}$

$\begin{array}{*{20}{l}} {\rm{4}} \end{array}$

$\begin{array}{*{20}{l}} {\rm{3}} \end{array}$

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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Analyzing +4 | -1

When two resistances

{R_1}\,\,\mathrm{and}\,\,{R_2}

are connected in series, they consume

\mathrm{12}\,\,\mathrm{W}

powers. When they are connected in parallel, they consume

\mathrm{50}\,\,\mathrm{W}

powers. What the ratio of the powers of

{R_1}\,\,\mathrm{and}\,\,{R_2}

View answer and explanation

Correct option: C

\begin{array}{llllllllllllllllllll} {\mathrm{3/2}} \end{array}

Option C (3/2) is correct because the ratio of powers of the two resistors is calculated by using the series and parallel power consumption equations.

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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