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JEE PHYSICS MCQ: GRAVITATION

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The height above the earth’s surface at which the acceleration due to gravity becomes 9% of its value at the surface is (

R

is radius of earth)

View answer and explanation

Correct option: D

\frac{{7R}}{3}

Option D (

\frac{{7R}}{3}

) is correct because the height is calculated using the formula for acceleration due to gravity at a height h,

g' = \frac{{GM}}{{{{\left( {R + h} \right)}^2}}}

, and setting it equal to 9% of g.

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