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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Sodium bicarbonate NaHCO3\mathrm{NaHCO}_3 can be purified by dissolving it in hot water (60∘C),\left(60^{\circ} \mathrm{C}\right), filtering to remove insoluble impurities, cooling to 0∘C0^{\circ} \mathrm{C} to precipitate solid NaHCO3,\mathrm{NaHCO}_3, and then filtering to remove the solid, leaving soluble impurities in solution. Any NaHCO3\mathrm{NaHCO}_3 that remains in the solution is not recovered. The solubility of NaHCO3\mathrm{NaHCO}_3 in hot water at 60∘C60^{\circ} \mathrm{C} is 164 g/164 \mathrm{~g} / litre and is 69 g/litre69 \mathrm{~g/litre} in cold water at 0∘C.0^{\circ} \mathrm{C}. What is the percentage yield of NaHCO3,\mathrm{NaHCO}_3, when it is purified by this method?
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Correct option: A
57.93%57.93 \%
Option A (57.93%57.93 \%) is correct because the percentage yield is calculated by finding the difference in solubility between hot and cold water, then dividing by the solubility in hot water.

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