One mole of an ideal gas undergoes a reversible process in which the entropy of the gas changes with absolute temperature $T$ as $S=a T+C_{\mathrm{v}, \mathrm{m}}$ $\ln T,$ where $a$ is a positive constant. If $T=T_0$ at $V=V_0,$ then the volume dependence of the gas on temperature in this process is

$T=T_0+\frac{R}{a} \cdot \ln \frac{V_0}{V}$

$V=V_0+\frac{a}{R} \cdot \ln \frac{T}{T_{0}}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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One mole of an ideal gas undergoes a reversible process in which the entropy of the gas changes with absolute temperature

T

S=a T+C_{\mathrm{v}, \mathrm{m}}

\ln T,

where

a

is a positive constant. If

T=T_0

V=V_0,

then the volume dependence of the gas on temperature in this process is

View answer and explanation

Correct option: C

T=T_{0}+\frac{R}{a} \cdot \ln \frac{V}{V_{0}}

Option C is correct because it represents the derived relationship between temperature and volume based on the given entropy equation and thermodynamic principles.

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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