JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

|z|=2

and locus of

5 z-1

is the circle having radius

a

and

z_1^2+z_2^2-2 z_1 z_2 \cos \theta=0

, then

\left|z_1\right|:\left|z_2\right|

is equal to

View answer and explanation

Correct option: C

a: 10

Option C (

a: 10

) is correct because it correctly relates the radius of the locus of

5z-1

to the ratio of

|z_1|

and

|z_2|

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