JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

For

x \geq 0,

the least value of

K,

for which

4^{1+x}+4^{1-x},

\frac{{K}}{2},

16^{{x}}+16^{-{x}}

are three consecutive terms of an A.P. is equal to:

View answer and explanation

Correct option: A

Option A (10) is correct because the minimum value of K is found by using the AM-GM inequality on the terms of the arithmetic progression.

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