Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities ${\omega _1}{\rm{\; and\; }}{\omega _2}.$ They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is

$\frac{I}{8}{({\omega _1} - {\omega _2})^2}$

${2^{I({\omega _1} + {\omega _2})}}$

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities

{\omega _1}\mathrm{\; and\; }{\omega _2}.

They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is

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Correct option: C

\frac{1}{4}I{({\omega _1} - {\omega _2})^2}

Option C (

\frac{1}{4}I{({\omega _1} - {\omega _2})^2}

) is correct because it represents the loss of kinetic energy due to the change in angular velocity after the discs are joined.

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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