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NEET UG CHEMISTRY MCQ: STATES OF MATTER

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Application +4 | -1
Calculate the compressibility factor for CO2\mathrm{CO}_2, if one mole of it occupies 4 litre at 300 K300 \mathrm{~K} and 4 atm. (R=0.082 L atm K−1 mol−1)\text {(} \left.\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)
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Correct option: A
0.65
Option A (0.65) is correct because the compressibility factor is calculated using Z = PV/nRT.

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