On a new scale of temperature (which is linear) and called the scale, the freezing and boiling points of water are ${39^{\rm{o}}}W$ and ${239^{\rm{o}}}W$ respectively. What will be the temperature on the new scale, corresponding to a temperature of ${39^{\rm{o}}}C$ on the Celsius scale

NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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On a new scale of temperature (which is linear) and called the scale, the freezing and boiling points of water are

{39^\mathrm{o}}W

and

{239^\mathrm{o}}W

respectively. What will be the temperature on the new scale, corresponding to a temperature of

{39^\mathrm{o}}C

on the Celsius scale

View answer and explanation

Correct option: D

{117^\mathrm{o}}W

Option D (

{117^\mathrm{o}}W

) is correct because it is the temperature on the new scale corresponding to 39°C on the Celsius scale.

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60 \mathrm{~cm} \times 50 \mathrm{~cm} \times 20 \mathrm{~cm}

1 \mathrm{~cm}

0^{\circ} \mathrm{C}

40^{\circ} \mathrm{C}

3.4 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}

\left. {0.05{\text{W}}{{\text{m}}^{ - 1}}^\circ {{\text{C}}^{ - 1}}} \right)

2 \times 10^5 \mathrm{~J} / \mathrm{sm}^2

127^{\circ} \mathrm{C}

32 \times 10^5 \mathrm{~J} / \mathrm{s}-\mathrm{m}^2

\sigma

+ \frac{1}{2}