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NEET UG PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
One mole of an ideal monatomic gas is taken from state A\mathrm{A} to state B through the process P=(3/2)T1/2P=(3 / 2) T^{1 / 2}. It is found that its temperature increases by 100Β K100 \mathrm{~K} in this process. Now it is taken from state B to C through a process for which internal energy is related to volume as UintΒ =(1/2)V1/2U_{\text {int }}=(1 / 2) V^{1 / 2}. Find the total work performed by the gas (in joule), if it is given that volume at B\mathrm{B} is 100Β m3100 \mathrm{~m}^3 and at C it is 1600Β m31600 \mathrm{~m}^3. (Use R=8.3Β J/molKR=8.3 \mathrm{~J} / \mathrm{mol} \mathrm{K}.)
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Correct option: A
435
The total work performed by the gas is 435 J. The work done in process A to B is calculated using the given relation P = (3/2)T(1/2) and the ideal gas law. The work done in process B to C is calculated using the relation between internal energy and volume.

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