If $l = \mathop {\lim }\limits_{x \to - 2} \frac{{\tan \pi {\rm{ }}x}}{{x + 2}} + \mathop {\lim }\limits_{x \to \infty } {\left( {1 + \frac{1}{{{x^2}}}} \right)^x}$ then which one of the following is not correct?

JEE MATHEMATICS MCQ: LIMITS

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l = \lim\limits_{x \to - 2} \frac{{\tan \pi \mathrm{ }x}}{{x + 2}} + \lim\limits_{x \to \infty } {\left( {1 + \frac{1}{{{x^2}}}} \right)^x}

then which one of the following is not correct?

View answer and explanation

Correct option: C

l < 4

Option

l < 4

is not correct because the value of

l

\pi + 1

, which is greater than 4.

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